Complex numbers problems with solutions
Complex numbers exercise :
Solve the following two equations in the set of complex numbers:
Z²- 2Z + 5 =0
Z² - 2(1+√3)Z + 5 + 2√3 = 0
in Orthogonal coordinates (o;i⇀,j⇀) We consider the points A , B , C and D are the images of complex numbers 1+2i , 1+√3 +i , 1-2i , 1+√3-i respectively.
a) What is the nature of the triangle ABC ?
b) Write the equation of the circle C around the triangle ABC.
c) Prove that the point D belongs to the circle C.
d) Create C And the points A, B, C and D in the Orthogonal coordinates.
solution of the example :
Solve the following two equations in the set of complex numbers
Z ²- 2Z + 5 =0
Z² - 2(1+√3)Z + 5 + 2√3 = 0
A) Z ²- 2Z + 5 =0
Calculate the discriminant :
Δ= (-2)²-4(5) = - 16 = (4i)²
Z1 = (2-4i)/2 = 1+2i , Z2 = (2+4i)/2 = 1+2i
Z2 = [2(1+✓3)+2i]/2 = 1+√3+i
a) The nature of the triangle ABC:
b) The equation of the circle C around the triangle ABC.
M (x;y) ∈ C this means.
MA−→−⋅MC−→−=0
MA−→−=(1−x−2−y),MC−→−=(1−x2−y)
MA−→−⋅MC−→−=0
this means: (1-x) (1-x) + (2-y) (-2-y)=0
1-x-x+x²-4-2y+2y+y²=0
x²+y²-2x-3=0
c) Prove that the point D belongs to the circle C.
(1+√3)²+(-1)² - 2(1+√3) -3 = 1+3+2√3 +1-2-2√3-3=0
then the point D belongs to the circle C .
d) Create C And the points A, B, C and D in the Orthogonal coordinates.